Reaction stoichiometry
Limiting reagentCompound
Molar Mass
WeightHCl(aq)236.46 K2SO3(s)1158.26 H2O(l)118.02 KCl(aq)274.55 SO2(g)164.06 Units: molar mass - g/mol, weight - g.Please tell about this free chemistry software to your friends!Direct links to this balanced equation:

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For the reaction 2 HCl(aq) + K2SO3(s


(1). Simply look at the coefficients in the balanced equation. The coefficient for HCl is 2 và that for K2SO3 is 1, so the mole ratio is 2 : 1

(2). Find moles of HCl and then since the mol ratio of HCl : K2SO3 is 2:1 (as determined above), we can find moles K2SO3 and then grams of K2SO3.

moles HCl = 26.5 ml x 1 L/1000 ml x 3.0205 mol/L = 0.08800 moles HCl

moles K2SO3 = 0.0800 mol HCl x 1 mol K2SO3 / 2 mol HCl = 0.0400 moles K2SO3 needed

mass K2SO3 needed = 0.0400 mol K2SO3 x 158 g/mol = 6.32 g K2SO3 needed (3 sig. Figs.)

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